Answer
$P_2=2.58kPa$
Work Step by Step
$P_1 = 6.58kPa$; $T_1 = 539K$; $T_2=211K$
$\frac{P_1}{T_1}=\frac{P_2}{T_2}$
$P_2=2.58kPa$
Chemistry (12th Edition)
by Wilbraham
Published by
Prentice Hall
ISBN 10:
0132525763
ISBN 13:
978-0-13252-576-3
Chapter 14 - The Behavior of Gases - 14 Assessment - Page 480: 61
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