Answer
87.1% yield
Work Step by Step
75.0 g FeCO3 x (1 mol FeCO3/115.86 g FeCO3) * (1 mol Fe2O3/2 mol FeCO3) * (159.7 g FeCO3/ 1 mol Fe2O3) = 51.6895, which is a 87.1% yield
Chemistry (12th Edition)
by Wilbraham
Published by
Prentice Hall
ISBN 10:
0132525763
ISBN 13:
978-0-13252-576-3
Chapter 12 - Stoichiometry - 12 Assessment - Page 412: 58
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
