Answer
a)11.25 moles of CO
22.5 moles of H₂
11.25 moles CH₃OH
b)16 g of H₂
112 g of CO
112 g CH₃OH
c)11.4 g of H₂
Work Step by Step
refer to attached image
Chemistry (12th Edition)
by Wilbraham
Published by
Prentice Hall
ISBN 10:
0132525763
ISBN 13:
978-0-13252-576-3
Chapter 12 - Stoichiometry - 12 Assessment - Page 411: 46
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