Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 4 - The Structure of Atoms - Exercises - Atomic Composition, Isotopes, and Atomic Weights - Page 164: 24

Answer

The symbol of an element X can be demonstrated as, $_{Atomic number } ^{Mass number }X$ Atomic number = Number of protons(p) Mass number = Number of protons(p) + Number of neutrons (n) = p+ n a) The number of protons(p) = 24, hence atomic number is 24 and it denotes Chromium (Cr). Mass number = p + n = 24 + 28 = 52 p = e = 24, means atom is neutral. Hence it’s symbol is, $_{24} ^{52}Cr$ b) The number of protons(p) = 20, hence atomic number is 20 and it denotes Calcium (Ca). Mass number = p + n = 20 + 20 = 40 p = e = 20, means atom is neutral. Hence it’s symbol is, $_{20} ^{40}Ca$ c) The number of protons(p) = 33, hence atomic number is 33 and it denotes Arsenic (As). Mass number = p + n = 33 + 42 = 65 p = e = 33, means atom is neutral. Hence it’s symbol is, $_{33} ^{65}As$ d) The number of protons(p) = 53 hence atomic number is 24 and it denotes Iodine (I). Mass number = p + n = 53 + 74 = 127 p = e = 53, means atom is neutral. Hence it’s symbol is, $_{53} ^{127}I$

Work Step by Step

The symbol of an element X can be demonstrated as, $_{Atomic number } ^{Mass number }X$ Atomic number = Number of protons(p) Mass number = Number of protons(p) + Number of neutrons (n) = p+ n a) The number of protons(p) = 24, hence atomic number is 24 and it denotes Chromium (Cr). Mass number = p + n = 24 + 28 = 52 p = e = 24, means atom is neutral. Hence it’s symbol is, $_{24} ^{52}Cr$ b) The number of protons(p) = 20, hence atomic number is 20 and it denotes Calcium (Ca). Mass number = p + n = 20 + 20 = 40 p = e = 20, means atom is neutral. Hence it’s symbol is, $_{20} ^{40}Ca$ c) The number of protons(p) = 33, hence atomic number is 33 and it denotes Arsenic (As). Mass number = p + n = 33 + 42 = 65 p = e = 33, means atom is neutral. Hence it’s symbol is, $_{33} ^{65}As$ d) The number of protons(p) = 53 hence atomic number is 24 and it denotes Iodine (I). Mass number = p + n = 53 + 74 = 127 p = e = 53, means atom is neutral. Hence it’s symbol is, $_{53} ^{127}I$
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