Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 3 - Chemical Equations and Reaction of Stoichiometry - Exercises - Concentrations of Solutions - Molarity - Page 110: 68

Answer

Molarity = 0.00940 M

Work Step by Step

Molarity = Number of moles/ Volume of solution in litre Mass of $BaCl_{2}.2H_{2}O$ = 1.72 g Molar mass of $BaCl_{2}.2H_{2}O$ = 244.26 g/mol Number of moles = Given mass/Molar mass Number of moles of $BaCl_{2}.2H_{2}O$ = 1.72g/244.26(g/mol) = 0.00704 mol Volume in litres = 0.750 l Molarity = 0.00704 mol/0.750 l = 0.00940 M
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