Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 18 - Ionic Equilibria I: Acids and Bases - Exercises - The pH and pOH Scales - Page 744: 50

Answer

(a) 4.143 (b) 9.377

Work Step by Step

(a) 1. Calculate the pKa Value $pKa = -log(Ka)$ $pKa = -log( 7.2 \times 10^{- 5})$ $pKa = 4.143$ (b) 1. Calculate the pKa Value $pKa = -log(Ka)$ $pKa = -log( 4.2 \times 10^{- 10})$ $pKa = 9.377$
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