Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 17 - Chemical Equilibrium - Exercises - Calculation of K - Page 702: 25

Answer

$K_c = 2.6 \times 10^{-9}$

Work Step by Step

1. Write the equilibrium constant expression: - The exponent of each concentration is equal to its balance coefficient. $K_c = \frac{[Products]}{[Reactants]} = \frac{[ Br_2 ][ F_2 ]^{ 5 }}{[ BrF_5 ]^{ 2 }}$ 2. Substitute the values and calculate the constant value: $K_c = \frac{( 0.0018 )( 0.0090 )^{ 5 }}{( 0.0064 )^{ 2 }} = 2.6 \times 10^{-9}$
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