Answer
$NH_3(aq) + H_2O(l) \leftrightharpoons NH{_4}^+(aq) + OH^-(aq)$
$HS^-(aq) + H_2O(l) \leftrightharpoons H_2S(aq) + OH^-(aq)$
$CH_3COO^-(aq) + H_2O(l) \leftrightharpoons CH_3COOH(aq) + OH^-(aq)$
$O^{2-}(aq) + H_2O(l) \leftrightharpoons 2 OH^-(aq)$
Work Step by Step
Since these are bases, they will receive a proton from water, producing their conjugate acid and the hydroxide ion.