Answer
$A = 1.12~R^2$
Work Step by Step
$A = [5~\frac{sin~A~sin~B}{sin~(A+B)}]~R^2$
$A = [5~\frac{sin~18^{\circ}~sin~36^{\circ}}{sin~(18^{\circ}+36^{\circ})}]~R^2$
$A = [5~\frac{(0.309017)(0.587785)}{(0.809017)}]~R^2$
$A = 1.12~R^2$
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Chapter 7 - Applications of Trigonometry and Vectors - Section 7.2 The Ambiguous Case of the Law of Sines - 7.2 Exercises - Page 306: 42
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