Chapter 7 - Applications of Trigonometry and Vectors - Section 7.2 The Ambiguous Case of the Law of Sines - 7.2 Exercises - Page 305: 39

$\frac{a+b}{b} = \frac{sin~A+sin~B}{sin~B}$

We can use the law of sines to find an expression for $a$: $\frac{a}{sin~A} = \frac{b}{sin~B}$ $a = \frac{b~sin~A}{sin~B}$ We can prove the statement in the question: $\frac{a+b}{b} = \frac{\frac{b~sin~A}{sin~B}+b}{b}$ $\frac{a+b}{b} = \frac{b~(\frac{sin~A}{sin~B}+1)}{b}$ $\frac{a+b}{b} = \frac{sin~A}{sin~B}+1$ $\frac{a+b}{b} = \frac{sin~A}{sin~B}+\frac{sin~B}{sin~B}$ $\frac{a+b}{b} = \frac{sin~A+sin~B}{sin~B}$