Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Test - Page 288: 19b

Answer

$x = \frac{\sqrt{3}}{3}$

Work Step by Step

$arccot~x+2~arcsin~\frac{\sqrt{3}}{2} = \pi$ $arccot~x+(2)(\frac{\pi}{3}) = \pi$ $arccot~x = \frac{\pi}{3}$ $x = cot(\frac{\pi}{3})$ $x = \frac{1}{\sqrt{3}}$ $x = \frac{1}{\sqrt{3}}~\times~\frac{\sqrt{3}}{\sqrt{3}}$ $x = \frac{\sqrt{3}}{3}$
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