Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Review Exercises - Page 286: 66b

Answer

$\theta = 90^{\circ}$

Work Step by Step

$L = 6077-31~cos~2\theta$ $6108 = 6077-31~cos~2\theta$ $31~cos~2\theta = 6077-6108$ $cos~2\theta = -\frac{31}{31}$ $2\theta = arccos(-1)$ $\theta = \frac{1}{2}~arccos(-1)$ $\theta = 90^{\circ}$
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