Answer
true
Work Step by Step
RECALL:
The tangent function's range is the set of all real numbers.
This means that $\tan^{-1}{x}$ will always be defined for any value of $x$.
Since t$\tan{x}$ and $\tan^{-1}{x}$ are inverse functions of each other, then $\tan{(\tan^{-1}{x})}=x$.
Therefore, the given statement is true.
