Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.3 Trigonometric Equations II - 6.3 Exercises - Page 274: 47a

Answer

We can see a sketch of the graph in the viewing window $[0,0.03]$ by $[-0.005, 0.005]$

Work Step by Step

$P = 0.003~sin~220~\pi~t+\frac{0.003}{3}~sin~660~\pi~t+\frac{0.003}{5}~sin~1100~\pi~t+\frac{0.003}{7}~sin~1540~\pi~t$ We can see a sketch of the graph in the viewing window $[0,0.03]$ by $[-0.005, 0.005]$
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