Answer
1) Given equation seems to be quadratic, but constant term is not present hence it can be converted to linear by dividing both the sides by $\sec x$.
2) Only one trigonometric function i.e. $\sec x$ is present.
3) Equation must be solved for $\sec x$ first.
3) Now equation can be solved for $x$.
Work Step by Step
Given equation is-
$5 \sec^{2} x$ = $6 \sec x$
Steps to be taken-
1) Given equation seems to be quadratic, but constant term is not present hence it can be converted to linear by dividing both the sides by $\sec x$.
2) Only one trigonometric function i.e. $\sec x$ is present.
3) Equation must be solved for $\sec x$ first.
3) Now equation can be solved for $x$.
