Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.3 Finding Trigonometric Function Values Using a Calculator - 2.3 Exercises - Page 65: 56

Answer

False

Work Step by Step

$\tan ^{2} (72^{\circ} 25') + 1 = \sec ^{2} (72^{\circ}25')$ $9.957710155 + 1 \ne 0.091259944264$
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