Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.5 Polar Equations and Graphs - 8.5 Exercises - Page 396: 80

Answer

The two points of intersection are: $(3, \frac{\pi}{3})$ and $(3, \frac{5\pi}{3})$

Work Step by Step

$r = 3$ $r = 2+2~cos~\theta$ To find the points of intersection, we can equate the expressions for $r$: $3 = 2+2~cos~\theta$ $2~cos~\theta = 1$ $cos~\theta = \frac{1}{2}$ $\theta = \frac{\pi}{3}, \frac{5\pi}{3}$ We can find $r$: $r = 3$ The two points of intersection are: $(3, \frac{\pi}{3})$ and $(3, \frac{5\pi}{3})$
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