Answer
$\frac{8}{\sqrt{3}+i}$
= $2\sqrt{3} - 2i$
Work Step by Step
$\frac{8}{\sqrt{3}+i}$
= $\frac{8cis0^\circ}{2cis30^\circ}$
= $4cis(0-30)^\circ$
= $4\cdot cos(-30^\circ) + 4i\cdot sin(-30^\circ)$
= $4\cdot \frac{\sqrt{3}}{2} - 4i\cdot \frac{1}{2}$
= $2\sqrt{3} - 2i$
