Answer
The rectangular form is $\frac{\sqrt{2}}{2} - \frac{\sqrt{6}}{2} i$
Work Step by Step
$\sqrt{2}(cos(-60^\circ)$ + $isin(-60^\circ))$
= $\sqrt{2} \cdot \frac{1}{2}$ + $\sqrt{2} \cdot i \cdot (- \frac{\sqrt{3}}{2})$
= $\frac{\sqrt{2}}{2} - \frac{\sqrt{6}}{2} i$
The rectangular form is $\frac{\sqrt{2}}{2} - \frac{\sqrt{6}}{2} i$
