Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Applications of Trigonometry and Vectors - Summary Exercises on Applications of Trigonometry and Vectors - Page 345: 7c

Answer

The speed of the wind $u$ is 11.3 mph. The wind is blowing toward the northwest direction at a bearing of $315^{\circ}$.

Work Step by Step

$u = -8~i+8~j$ The speed of the wind is the magnitude of the vector $u$. We can find the magnitude of the vector $u$: $\vert u \vert = \sqrt{(-8)^2+8^2}$ $\vert u \vert = 11.3$ The wind is blowing toward the northwest. Since the horizontal component is equal in magnitude to the vertical component, the wind is blowing at a bearing of $270^{\circ}+45^{\circ} = 315^{\circ}$. The speed of the wind $u$ is 11.3 mph. The wind is blowing toward the northwest direction at a bearing of $315^{\circ}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.