Answer
There is one possible triangle with the given parts.
$A = 48^{\circ}, B = 39^{\circ},$ and $C = 93^{\circ}$
Work Step by Step
We can use the law of sines to find the angle $B$:
$\frac{a}{sin~A} = \frac{b}{sin~B}$
$sin~B = \frac{b~sin~A}{a}$
$sin~B = \frac{(26)~sin~(48^{\circ})}{31}$
$B = arcsin(0.623)$
$B = 39^{\circ}$
We can find angle $C$:
$A+B+C = 180^{\circ}$
$C = 180^{\circ}-A-B$
$C = 180^{\circ}-48^{\circ}-39^{\circ}$
$C = 93^{\circ}$
Note that we can also find another angle for B.
$B = 180-39^{\circ} = 141^{\circ}$
However, we can not form a triangle with this angle B and angle A since these two angles sum to more than $180^{\circ}$
