Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Test - Page 293: 11

Answer

$\theta = 135^{\circ}~~$ or $~~\theta = 315^{\circ}$

Work Step by Step

$csc^2~\theta - 2~cot~\theta = 4$ $\frac{1}{sin^2~\theta} - \frac{2~cos~\theta}{sin~\theta} = 4$ $\frac{1}{sin^2~\theta} - \frac{2~sin~\theta~cos~\theta}{sin^2~\theta} = 4$ $1 - 2~sin~\theta~cos~\theta = 4~sin^2~\theta$ $(sin^2~\theta+cos^2~\theta) - 2~sin~\theta~cos~\theta = 4~sin^2~\theta$ $(sin~\theta-cos~\theta)^2 = 4~sin^2~\theta$ $sin~\theta-cos~\theta = 2~sin~\theta$ $-cos~\theta = sin~\theta$ $tan~\theta = -1$ $\theta = 135^{\circ}~~$ or $~~\theta = 315^{\circ}$
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