Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.3 Trigonometric Equations II - 6.3 Exercises - Page 280: 53

Answer

$x = 0.4636~~$ or $~~x=3.6052$

Work Step by Step

$tan~2x+sec~2x = 3$ $tan~2x= 3-sec~2x$ $tan^2~2x= 9-6~sec~2x+sec^2~2x$ $sec^2~2x-1= 9-6~sec~2x+sec^2~2x$ $6~sec~2x= 10$ $sec~2x= \frac{5}{3}$ $cos~2x= \frac{3}{5}$ $2x = 0.9273~~$ or $~~2x=7.2105$ $x = 0.4636~~$ or $~~x=3.6052$
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