Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.2 Trigonometric Equations I - 6.2 Exercises - Page 273: 17

$x = \frac{\pi}{6}, \frac{5\pi}{6}$

$2\sin x + 3= 4$ $2\sin x = 4 - 3$ $2\sin x = 1$ $\sin x = \frac{1}{2}$ $x = \frac{\pi}{6}, \frac{5\pi}{6}$ $= \pi - \frac{\pi}{6}$ $= \frac{6\pi}{6} - \frac{\pi}{6}$ $=\frac{5\pi}{6}$