Answer
30$^{\circ}$F
Work Step by Step
Since January is represented by $x=0$, we substitute $x=0$ in the equation to find the value of $t$:
$t=60-30\cos\frac{x\pi}{6}$
$t=60-30\cos\frac{0\pi}{6}$
$t=60-30\cos\frac{0}{6}$
$t=60-30\cos 0$
$t=60-30(1)$
$t=30$
Therefore, the maximum afternoon temperature for the month of January is 30$^{\circ}$F.
