Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Graphs of the Circular Functions - Section 4.5 Harmonic Motion - 4.5 Exercises - Page 186: 19b

Answer

$\frac{\pi}{6}$ seconds

Work Step by Step

Period P is the reciprocal of frequency F. Since the frequency is $\frac{6}{\pi}$ cycles per second, Period$=\frac{1}{\frac{6}{\pi}}=\frac{\pi}{6}$ seconds
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