Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises - Page 150: 47b

Answer

15

Work Step by Step

The amplitude of a periodic function is half the difference between the maximum and minimum values. Since the maximum value is 80 while the minimum value is 50, Amplitude$=\frac{1}{2}(80-50)$ Amplitude$=\frac{1}{2}(30)$ Amplitude$=15$
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