Answer
1; $2\pi$
Work Step by Step
Amplitude of $y=a\sin x$ and $y=a\cos x$ is given by
Amplitude=$|a|$
Since $a=1$ here, we have
Amplitude=$|1|=1$
Period of a periodic function
$f(x)= f(x+np)$ is the least possible positive value $p$ where $n$ is an integer and $x$ belongs to the domain of $f$.
$\sin x=\sin(x+n\cdot2\pi)$
$\cos x= \cos (x+n\cdot2\pi)$
This implies that $2\pi$ is the period of sine and cosine functions.