Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises - Page 148: 1

Answer

1; $2\pi$

Work Step by Step

Amplitude of $y=a\sin x$ and $y=a\cos x$ is given by Amplitude=$|a|$ Since $a=1$ here, we have Amplitude=$|1|=1$ Period of a periodic function $f(x)= f(x+np)$ is the least possible positive value $p$ where $n$ is an integer and $x$ belongs to the domain of $f$. $\sin x=\sin(x+n\cdot2\pi)$ $\cos x= \cos (x+n\cdot2\pi)$ This implies that $2\pi$ is the period of sine and cosine functions.
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