Answer
(a) $40\pi\,rad$
(b) $480\pi \,ft$
(c) $96\pi\,ft/min$
Work Step by Step
(a) $\omega=\frac{\theta}{t}$
$\implies \theta=\omega t=(8\pi\,rad/min)\times5\,min$
$=40\pi\,rad$
(b) Using the arc length formula,we have
Distance traveled $s=r\theta= (12\,ft)(40\pi)$
$=480\pi \,ft$
(c) Linear speed $v=r\omega$
$=12\,ft(8\pi\,rad/min)=96\pi\,ft/min$