Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 95: 50

Answer

$\theta=22.62^{o}$ $r=13$

Work Step by Step

Horizontal and vertical diopters .... are at a right angle, so the dashed side is a leg of a right triangle and has length 5 . $(SOHCAHTOA)$ The side opposite to $\theta$ is 5, the side adjacent to it is 12, $\displaystyle \tan\theta=\frac{5}{12}$ $\displaystyle \theta=\tan^{-1}(\frac{5}{12})\approx$22.619864948$\approx 22.62^{o}$ r is the hypotenuse...Pythagorean theorem: $r^{2}=5^{2}+12^{2}$ $r^{2}=25+144$ $r^{2}=169$ $r=13$
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