Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.4 Solving Right Triangles - 2.4 Exercises - Page 78: 17

Answer

$z \approx 84.816 cm$ $x \approx 62.942 cm$ $\angle X = 47.9108^{\circ}$

Work Step by Step

1. $\angle Y = 42.0892^{\circ}$ $y= 56.851 cm$ 2. $\angle Y +\angle X = 90^{\circ}$ $\angle X = 47.9108^{\circ}$ 3. $\sin Y = \frac{y}{z}$ $z= 56.851 \times \sin (42.0892^{\circ}) \approx 84.816 cm$ 4. $\tan Y = \frac{y}{x}$ $x= 56.851 \times \tan (42.0892^{\circ}) \approx 62. 942 cm$
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