Answer
The coordinates are $P=(1, \sqrt 3)$.
Work Step by Step
To calculate the coordinates of $P$, remember the formula for polar coordinates: $P=(r\cos\theta, r\sin\theta)$
In this case, $r=2$ and $\theta=60^{\circ}$
Substituting in the formula,
$P=(2\cos(60^{\circ}), 2\sin(60^{\circ}))$
$P=(2*\frac{1}{2}, 2*\frac{\sqrt 3}{2})$
$P=(1, \sqrt 3)$
