Answer
$\sin$ A = $\frac{45}{53}$
$\cos$ A = $\frac{28}{53}$
$\tan$ A = $\frac{45}{28}$
Work Step by Step
$\sin$ = $\frac{perpendicular}{hypotenuse}$
$\cos$ = $\frac{base}{hypotenuse}$
$\tan$ = $\frac{perpendicular}{base}$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 53: 8
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