Answer
I
Work Step by Step
Because $\sin\theta\gt0$ in quadrants I and II and $\tan\theta\gt0$ in quadrants I and III, both conditions are met only in quadrant I.
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 1 - Trigonometric Functions - Section 1.4 Using the Definitions of the Trigonometric Functions - 1.4 Exercises - Page 37: 4
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