Answer
0
Work Step by Step
1.First lets find the values of the trig functions of the given angles.
$\sec180^{\circ}=-1$
$\sin360^{\circ}=0$
$\cos180^{\circ}=-1$
2. Then just plug those values into expression:
$(-1)^{2} -3(0)^{2}+(-1) =0$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 29: 93
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