Answer
$-\frac{\sqrt 2}{2}$
Work Step by Step
$r=\sqrt {x^{2}+y^{2}}=\sqrt {(-3)^{2}+(-3)^{2}}=3\sqrt 2$
$\cos\theta=\frac{x}{r}=\frac{-3}{3\sqrt 2}=-\frac{1}{\sqrt 2}=-\frac{\sqrt 2}{2}$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 27: 9
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