Answer
$CG~feet = EG~paces$
Work Step by Step
$\frac{CG~feet}{1~foot} = \frac{AG}{AD} = \frac{EG}{BD} = \frac{EG~paces}{1~pace}$
$\frac{CG~feet}{1} = \frac{EG~paces}{1}$
$CG~feet = EG~paces$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 1 - Trigonometric Functions - Section 1.2 Angle Relationships and Similar Triangles - 1.2 Exercises - Page 20: 74d
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