Answer
Refer to the curve in Black in Graph I
Work Step by Step
For $f(x) = \sqrt{x} - 2$
when
$x = 9, y = 1;$
$x = 4, y = 0;$
$x = 1, y = -1;$
$x = 0, y = -2$
As seen, $f(x) = \sqrt{x} - 2$ is the vertical translation down by 2 units of $f(x) = \sqrt{x}$.
Domain = $[0, \infty)$
Range = $[-2, \infty)$