Answer
Appendix D - 14 (Answer)
See Graph I
Work Step by Step
Appendix D - 14 (Solution)
For $y = \frac{1}{3} x^2$,
When
$x = 6, y = 12;$
$x = 3, y = 3;$
$x = 0, y = 0;$
$x = −3, y = 3;$
$x = −6, y = 12$
Domain = $(−\infty, \infty)$
Range = $[0, \infty)$
See Graph I