Answer
.1836
Work Step by Step
Using a z-table, we find:
P(X < 4933 or X > 5067) = P(Z < -1.33 or Z > 1.33) = 2P(Z < -1.33) = 2(.0918) = .1836
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 14 - Binomial Distributions - Chapter 14 Exercises - Page 343: 14.36
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