Answer
$54,6.6543$
Work Step by Step
The mean of a binomial distribution: $\mu=np=300\cdot0.18=54$
The standard deviation of a binomial distribution: $\sigma=\sqrt{npq}=\sqrt{np(1-p)}=\sqrt{200\cdot0.18\cdot(1-0.18)}=6.6543$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 14 - Binomial Distributions - Chapter 14 Exercises - Page 342: 14.34a
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