Answer
The chances that a randomly selected person is Asian given that he/she is glucose tolerant is:
P(A|L) = $\frac{P(A and L)}{P(L)}$
= $\frac{P(L|A) . P(A)}{P(L)}$
= (0.9 0.04) / (0.252)
= 0.14
Hence, 14% of the lactose tolerant people are Asian.
Work Step by Step
The chances that a randomly selected person is Asian given that he/she is glucose tolerant is:
P(A|L) = $\frac{P(A and L)}{P(L)}$
= $\frac{P(L|A) . P(A)}{P(L)}$
= (0.9 0.04) / (0.252)
= 0.14
Hence, 14% of the lactose tolerant people are Asian.
