Answer
1
Work Step by Step
We find:
$P(\text{A and B})+P(\text{A and not B})+P(\text{not A and B})+P(\text{not A and not B})\\=0.24+0.28+0.02+0.46=1$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 13 - General Rules of Probability - Apply Your Knowledge - Page 309: 13.4c
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