Answer
No.
Work Step by Step
$P(high \ BP|high C)=\frac{P(\text{high BP and high C)}}{P(high C)}=\frac{0.11}{0.11+0.21}=\frac{0.11}{0.32}\approx0.3438=34.38\%$
$P(high \ BP)=0.11+0.16=0.27=27\%$
Thus, no, because the probabilities are not the same.
