Answer
Yes.
Work Step by Step
$P(dog|female)=\frac{P(\text{dog and female)}}{P(female)}=\frac{16/42}{28/42}=\frac{16}{28}=\frac{4}{7}\approx0.5714=57.14\%$
$P(dog)=\frac{24}{42}=\frac{4}{7}\approx0.5714=57.14\%$
Thus, yes, because both probabilities are the same.
