Answer
$µ_{x̅1-x̅2} = 4$
$σ_{x̅1-x̅2} = 0.5$
Work Step by Step
$µ_{x̅1-x̅2} = 14 - 10 = 4 $
$σ_{x̅1-x̅2} = \sqrt ({4^{2}/100} + {3^{2}/100})$
= $\sqrt ({16/100}+{9/100}) = \sqrt (25/100) = 5/10 = 0.5$
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