Answer
P(CVSA will yield an incorrect result for at least one of the four suspects)
=$ P($ CVSA will yield proper result for all 4 subjects$)^{c}$
=$ P($ Sub1 ∩ Sub2 ∩ Sub3 ∩ Sub4$)^{c}$
=$1- P$ (Sub1 ∩ Sub2 ∩ Sub3 ∩ Sub4)
=$1- 0.922368$ $(P(S1∩ ... S4) = 0.98*0.98*0.98*0.98 = 0.922368)$
=$7.7632$%
Work Step by Step
Steps are in the main answer.
