Answer
$P$( All 3 kidneys match receiver) = $0.0000001$%
$P$( None of kidneys match receiver) = $99.7003$%.
Work Step by Step
Event A : 1st donor kidney matches receiver.
Event B : 2nd donor kidney matches receiver.
Event C : 3rd donor kidney matches receiver.
$P$( All 3 kidneys match receiver) = $P$(A∩B∩C)
$P$(A∩B∩C) = $P$(A)*$P$(B)*$P$(C)
$P$(A∩B∩C) = $0.001*0.001*0.001$
$P$(A∩B∩C) = $0.000000001$
$P$(None of 3 kidneys match receiver) = $P$(AUBUC$)^{c}$
$P$(AUBUC$)^{c}$ = 1- $P$(AUBUC)
$P$(AUBUC$)^{c}$ = 1- [0.002997] (Please see the picture below)
$P$(AUBUC$)^{c}$ = $0.997003 = 99.7003$%
