Answer
For A and B to be exclusive, P(A ∩ B) = 0, so
P((B|A) = P(A ∩ B) / P(A) = 0
So Bayes's rule is not needed
Work Step by Step
As given in answer
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 3 - Probability - Exercises 3.138 - 3.153 - Understanding the Principles - Page 166: 3.140
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