Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 3 - Probability - Exercises 3.138 - 3.153 - Learning the Mechanics - Page 166: 3.143

Answer

Since A is independant of B_{1}, B_{2} & B_{3}, P(B_{1}∩A) = P(B_{1}.P(A) P(B_{2}∩A) = P(B_{2}.P(A) P(B_{3}∩A) = P(B_{3}.P(A) P(B_{1}|A) = (PA∩(B_{1})/P(A) = P(A). P(B_{1}) / P(A) P(B_{1}|A) = P(B_{1}) = 0.2

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